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The volume of a sphere is increasing at the rate of 1200 cu.cm/s. The rate of increase in its surface area, when the radius is 10 cm, is_____.

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answer is 240.

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Detailed Solution

$\frac{d v}{d t} = \frac{r}{2} \frac{d s}{d t} \Rightarrow 1200 = \frac{10}{2} . \frac{d s}{d t} \Rightarrow \frac{d s}{d t} = 240$

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