The volume of a sphere of radius 10.5 cm is

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{9702 cm}^{3}

{19404 cm}^{3}

{4851 cm}^{3}

{14553 cm}^{3}

answer is B.

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Detailed Solution

$\begin{array}{l} r = 10.5 c m \\ V_{s p h e r e} = \frac{4}{3} π r^{3} \\ = \frac{4}{3} \times \frac{22}{7} \times \frac{21}{2} \times \frac{21}{2} \times \frac{21}{2} \\ = 11 \times 441 \\ = 4851 c m^{3} \end{array}$

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