The volume of air (containing 21% oxygen by volume) required to burn completely 1kg of carbon containing 100% combustible substances $(C + O_{2} \to {CO}_{2})$ is

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$8.8889 \times 10^{3} lit$

$10.0999 \times 10^{3} lit$

$9.999 \times 10^{4} lit$

$11.111 \times 10^{5} lit$

answer is A.

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Detailed Solution

$C + O_{2} \to {CO}_{2}$

$22.4 lit \to 12 g of C$

$? \to 1 \times 10^{3} g$

$\frac{1 \times 10^{3}}{12} \times 22.4 = 1.87 \times 10^{3} l i t s$

$100 lits of Air \to 21 lits of O_{2}$

$? \to 1.87 \times 10^{3} lits$

$= \frac{1.87 \times 10^{3}}{21} \times (100)$

= $8.8889 \times 10^{3} lit$ of Air.

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