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Q.

The volume of carbon dioxide at NTP evolved by strong heating of 20 g of calcium carbonate is
${CaCO}_{3} \to CaO + {CO}_{2}$

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a

4.0 lts

b

2.24 lts

c

8.0 lts

d

4.48 lts

answer is B.

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Detailed Solution

${CaCO}_{3} \to CaO + {CO}_{2}$

$100 g of {CaCO}_{3} \to 22.4 lit of {CO}_{2}$

$20 g of {CaCO}_{3} \to x lit of {CO}_{2}$

$Then x = \frac{20 g}{100 g} \times 22.4 lit = 4.48 lit$

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