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Q.

The volume of CO2 liberated at S.T.P and the quantity of heat energy liberated from the combustion of 2.3 g of ethyl alcohol is? 

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a

36 KJ

b

836 KJ

c

6836 KJ

d

68.36 KJ

answer is D.

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Detailed Solution

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l)+1367.2KJ/mole  
46gms of C2H5OH on combustion liberate 2×22.4lit of CO2 at STP acid 1367.2 of energy
On combustion of 2.3g of C2H5OH  
2.346×2×22.4=2.24lit
Energy liberated =2.346×1367.2=68.36 kj   

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