The volume of ${CO}_2$ obtained by the complete decomposition of one mole of ${NaHCO}_3$ at STP is ______.

 

The reaction of decomposition of Sodium bicarbonate is given below:

$2{\mathrm{NaHCO}}_3\to {\mathrm{Na}}_2{\mathrm{CO}}_3+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}$

From the reaction we can see that 2 moles of sodium bicarbonate will decompose into 1 mole of carbon dioxide.

So, 2 moles of Sodium bicarbonate will decompose into 22.4 L of volume at STP.

Hence, for 1 mole of Sodium bicarbonate will decompose = $\frac{22.4}{2}=11.2 \mathrm{L}$

Therefore, The volume of ${CO}_2$ obtained by the complete decomposition of one mole of ${\mathrm{NaHCO}}_3$ at STP is 11.2 L.