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The volume of gas $A$ is twice than that of gas B.The compressibility factor of gas $A$ is thrice than that of gas $B$ at same temperature the pressure of the gases for equal number of moles are

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$2 P_{A} = 3 P_{B}$

$3 P_{A} = 2 P_{B}$

$P_{A} = 2 P_{B}$

$P_{A} = 3 P_{B}$

answer is A.

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Detailed Solution

$z = \frac{p v}{n_{1} R T}$

$∴ n_{1} = n_{2} \frac{z_{1}}{z_{2}} = \frac{p_{1} v_{1}}{n_{1}} \times \frac{n_{2}}{p_{2} v_{2}}$

$3_{p B} = 2 P_{A}$

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