The volume of hydrogen liberated at 27°C and 760 mm of Hg pressure by treating 1.2 g of magnesium with excess of Hydrochloric acid is $Mg + 2 HCl \to {MgCl}_{2} + H_{2}$

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

1.23 litres

1.48 litres

1.35 litres

1.80 litres

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$Mg + 2 HCl \to {MgCl}_{2} + H_{2}$

$24 g \to 22.4 lit (H_{2})$

1.2g ----- ?

$= \frac{1.2}{24} \times 22.4 = 1.12 lit$

$PV = nRT \Rightarrow \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{760 \times 1.12}{273 K} = \frac{760 \times V_{2}}{300 K}$

$V_{2} = \frac{1.12 \times 300}{273}$

$V_{2} = 1.23 lit .$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE