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The volume of hydrogen liberated at 27°C and 760 mm of Hg pressure by treating 1.2 g of magnesium with excess of Hydrochloric acid is $Mg + 2 HCl \to {MgCl}_{2} + H_{2}$

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1.23 litres

1.48 litres

1.35 litres

1.80 litres

answer is A.

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Detailed Solution

$Mg + 2 HCl \to {MgCl}_{2} + H_{2}$

$24 g \to 22.4 lit (H_{2})$

1.2g ----- ?

$= \frac{1.2}{24} \times 22.4 = 1.12 lit$

$PV = nRT \Rightarrow \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$\frac{760 \times 1.12}{273 K} = \frac{760 \times V_{2}}{300 K}$

$V_{2} = \frac{1.12 \times 300}{273}$

$V_{2} = 1.23 lit .$

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