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Q.

The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is _______ x 10^-2L
Given : Molar volume of gas is 22.4 L at STP.
Molar mass of magnesium is 24 g mol^-1

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answer is 224.

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Detailed Solution

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$Mg + 2 HCl \to {MgCl}_{2} + H_{2}$
24 gm 22.4 lt
2.4 gms 2.24 lt
$2.24 lt = 224 \times 10^{- 2} lt$

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