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Q.

The volume of hydrogen liberated at STP by treating 2.4 g of magnesium with excess of hydrochloric acid is ______ $x 10^{- 2}$ L. Given Molar volume of gas is 22.4 L at STP. Molar mass of magnesium is 24 gmol^-1

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answer is 224.

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Detailed Solution

$Mg + 2HCl \to M g C l_{2} + H_{2}$

$24gm \to 22.4 l i t o f H_{2}$

$2.4gm \to ?$

$\frac{2.4 \times 22.4}{24} = 2.24$

$\underline{224 \times 10^{- 2} l i t}$

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