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Q.

The volume of nitrogen gas (measured at STP) required to cover a sample of silica gel with a monomolecular layer is $129 {cm}^{3} / g of gel.$ Calculate the surface area per gram of the gel if each nitrogen molecule occupies $16.2 \times 10^{- 20} m^{2}$ (Report your answer after dividing by 10).

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Detailed Solution

$22400 ml of N_{2} = 6 \times 10^{23} molecules 12 gmol = ? = \frac{6 \times 10^{23}}{22400} \times 129 molecules$
Surface area g^–1 of silica gel = area occupied
by each N₂ molecules × no. of N₂ molecules
$= 16.2 \times 10^{- 20} m^{2} \times \frac{6 \times 10^{23}}{22400} \times 129 = 560 m^{2}$

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The volume of nitrogen gas (measured at STP) required to cover a sample of silica gel with a monomolecular layer is 129cm3/g of gel. Calculate the surface area per gram of the gel if each nitrogen molecule occupies 16.2×10−20m2 (Report your answer after dividing by 10).