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The volume of the average adult lung when expanded is about 6 litre at ${98.4}^{0} F .$ If the pressure of oxygen in inhaled air is 168mm of Hg, calculate the mass of $O_{2}$ required to occupy the lung at ${98.4}^{0} F$

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answer is 2.

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Detailed Solution

$\frac{F - 32}{9} = \frac{C}{5}$

$\begin{array}{l} \frac{98.4 - 32}{9} = \frac{C}{5} \Rightarrow C = {36.88}^{0} c = 309.88 K \\ P V = \frac{W}{M} R T \\ \frac{168}{760} \times 6 = \frac{W}{32} \times 0.0821 \times 309.88 \\ W = 1.67 g = 2.0 \end{array}$

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