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The volume of the cylinder whose height is equal to diameter of the base ( where r is radius and h is height )

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$π \frac{r^{3}}{4}$

$2 π^{2} h$

$p \frac{h^{3}}{2}$

$2 {πr}^{3}$

answer is D.

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Detailed Solution

h = 2r

Volume of cylinder

$v = {πr}^{2} h = {πr}^{2} (2 r)$
$v = 2 {πr}^{3}$

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