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The volume of vessel $A$ is twice the volume of another vessel $B$ , and both of them are filled with the same gas. If the gas in $A$ is at twice the temperature and twice the pressure in comparison to the gas in $B$ , then the ratio of the gas molecules in $A$ to that of $B$ is

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$\frac{1}{2}$

$\frac{2}{1}$

$\frac{3}{2}$

$\frac{2}{3}$

answer is B.

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Detailed Solution

$P V = n R T n_{B} = \frac{P V}{R T}, n_{A} = \frac{2 P x 2 V}{R x 2 T}$

$\frac{n_{A}}{n_{B}} = \frac{2}{1}$

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