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The volume of water that must be added to a mixture of 250ml of 6M $H C l$ and 650ml of 3M $H C l$ to obtain 3M solution is

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75ml

150ml

300ml

250ml

answer is D.

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Detailed Solution

$M = \frac{M_{1} V_{1} + M_{2} V_{2}}{T o t a l v o l o f s o l u t i o n}$

$3 = \frac{250 \times 6 + 650 \times 3}{250 + 650 + x}$

x = volume of water added = 250 ml

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