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Q.

The volume of water that must be added to a mixture of 250ml of 6M HCl and 650ml of 3M HCl to obtain 3M solution is

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a

75 ml

b

300 ml

c

150 ml

d

250 ml

answer is D.

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Detailed Solution

$M = \frac{M_{1} V_{1} + M_{2} V_{2}}{(V_{1} + V_{2} + v o l . o f w a t e r)}$

$3 = \frac{250 \times 6 + 650 \times 3}{(250 + 650 + v o l . o f w a t e r)}$ $∴ v o l . o f w a t e r = 250 m l$

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