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Q.

The volume of water to be added to $100 {cm}^{3}$ of 0.5N $H_{2} {SO}_{4}$ to get decinormal concentration is

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a

${500 cm}^{3}$

b

${400 cm}^{3}$

c

${450 cm}^{3}$

d

${100 cm}^{3}$

answer is A.

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Detailed Solution

$\begin{array}{l} N_{1} V_{1} = N_{2} V_{2} \\ 0.5 \times 100 = 0.1 \times V_{2} \Rightarrow V_{2} = 500 c m^{3} \end{array}$

$∴$ water to be added to 100 $c m^{3}$ solution $= 500 - 100 = 400 c m^{3}$

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The volume of water to be added to 100 cm3 of 0.5N H2SO4 to get decinormal concentration is