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The volume of $0.1 M {Na}_{2} {SO}_{4}$ needed to be added to 10 mL of $0.1 M HCl$ to change the pH from 1.00 to 1.50 is: $(K_{2} = 1.26 x 10^{- 2} for H_{2} {SO}_{4})$

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6.6 mL

1.1 mL

4.4 mL

2.2 mL

answer is A.

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Detailed Solution

$\begin{array}{l} \underset{0.1 V - x}{{SO}_{4}^{2 -}} + \underset{1 - x}{H^{+}} ⇌ \underset{x}{{HSO}_{4}^{-}} \\ \Rightarrow x = 0.0715 V \end{array}$

Also, $\frac{1 - x}{V + 10} = 10^{- 15}$

Substituting, we get,

V = 6.6 mL

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