The volume of $O_{2}$ required for the complete combustion of 120 ${cm}^{3}$ of methane gas in a eudiometer tube will be:

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60 ${cm}^{3}$

120 ${cm}^{3}$

240 ${cm}^{3}$

360 ${cm}^{3}$

answer is C.

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Detailed Solution

${CH}_{4} + 2 O_{2} \to {CO}_{2} + 2 H_{2} O$

$22400 {cm}^{3} {CH}_{4} need O_{2}$ for complete combustion

$= 2 \times 22400 {cm}^{3}$

$120 {cm}^{3} {CH}_{4} need O_{2}$ for complete combustion

$\begin{array}{l} = \frac{2 \times 22400 {cm}^{3}}{22400 {cm}^{3}} \times 120 {cm}^{3} \\ = 240 {cm}^{3} \end{array}$

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