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The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is

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$\frac{4 RT}{V}$

$\frac{88 R T}{V}$

$\frac{3 RT}{V}$

$\frac{5}{2} \frac{RT}{V}$

answer is D.

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Detailed Solution

$\begin{array}{l} {P=P}_{O}_{_{2}} {+P}_{N}_{_{2}} {+PC}_{O}_{_{2}} \\ = \frac{1}{2} \frac{RT}{V} + \frac{RT}{V} + \frac{RT}{V} = \frac{5}{2} \frac{RT}{V} \end{array}$

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