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Q.

The wave length of first member of Balmer series of a hydrogen atom is nearly (The value of Rydberg constant R = 1.08 × 10⁷m^–1)

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a

4400A°

b

5500A°

c

6600A°

d

7700A°

answer is C.

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Detailed Solution

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$\frac{1}{λ} = R_{H} Z^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] \frac{1}{λ} = 1.08 \times 10^{7} \times 1^{2} [\frac{1}{2^{2}} - \frac{1}{3^{2}}] λ = 6.66 \times 10^{- 7} m \times \frac{1 \overset{°}{A}}{10^{- 10} m} = 6600 \overset{°}{A}$

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