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Q.

The wave number for the longest wavelength transition in the Balmer series of atomic hydrogen is

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a

1.5236 x 106 m-1

b

15236 x 1012 m-1

c

1.5236 x 108 m-1

d

1.5236 x 109 m-1

answer is A.

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Detailed Solution

In this question n1 = 2

n2 =3(Should be minimum energy difference for longest wave length)

according to Rydberg equation

Wave number=1.097x 107 x 5/36 m-1

=1.5236 x 106 m-1

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