The wave number of the first line is Balmer series of hydrogen in 15200 cm^–1. The wave number of the first line in the Balmer series of Li²⁺ is

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15200 cm^–1

60800 cm^–1

76000 cm^–1

136,800 cm^–1

answer is D.

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Detailed Solution

$\bar{v} = \frac{1}{λ} = R Z^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] = R \times 1^{2} [\frac{1}{2_{1}^{2}} - \frac{1}{3_{2}^{2}}] = 9 \times 15200 = 136800 c m^{- 1}$

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