The wave number of the third line of the Balmer series of hydrogen spectrum is $[R = Rydberg constant]$

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0.18 R

0.21 R

0.138 R

0.22 R

answer is A.

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Detailed Solution

$\bar{ϑ} = \frac{1}{λ} = R [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$ Third line $\bar{ϑ} = R [\frac{1}{2^{2}} - \frac{1}{5^{2}}]$ $\bar{ϑ} = R [\frac{1}{4} - \frac{1}{25}]$ $\bar{ϑ} = 0 .21 R$

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