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The wavelength is 110 cm when the source is stationary. If the source is moving with a velocity of 60 m/sec towards the stationary observer, then the wavelength of the sound wave reaching to the observer will be (velocity of sound = 330 m/s)

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110 cm

130 cm

90 cm

60 cm

answer is C.

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Detailed Solution

$n^{'} = n (\frac{v}{v - v_{s}})$ $\Rightarrow λ^{'} = λ (\frac{v - v_{S}}{v})$

$\Rightarrow λ^{'} = 110 (\frac{330 - 60}{330}) = 90 c m .$

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