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The wavelength of a ball bearing of mass 2.0 g moving with a velocity of 100 ms^-1 in metres is:

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$3.313 \times 10^{- 33}$

$6.626 \times 10^{- 33}$

$3.313 \times 10^{- 34}$

$6.626 \times 10^{- 34}$

answer is D.

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Detailed Solution

$λ = \frac{h}{m v}$

$m = 2.0 g = 0.002 k g = 2.0 \times 10^{- 3} k g$

$v = 100 m s^{- 1} \leq$

$λ = \frac{6.626 \times 10^{- 34} J s (k g m^{2} s^{- 1})}{2 \times 10^{- 3} k g \times 100 m s^{- 1}}$

$= 3.313 \times 10^{- 33} m$

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