The wavelength of a certain line in Balmer Series is observed to be 4329 A°. To what value of ‘n’ does this correspond ? (R_H = 109678 cm^–1) (Z = 1)

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Detailed Solution

$\begin{array}{l} \frac{1}{λ} = R_{H} Z^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] \\ \Rightarrow \frac{1}{4329 \times 10^{- 8}} = 1 .09678 \times 10^{5} [\frac{1}{4} - \frac{1}{n_{2}^{2}}] \\ ∴ n_{2} = 5 \end{array}$

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