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The wavelength of a particle is 99 cm and that of other is 100 cm. Speed of sound is 396 m/s. The number of beats heard per sec is

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answer is A.

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Detailed Solution

$Δn = v [\frac{1}{λ_{1}} - \frac{1}{λ_{2}}] = 396 [\frac{1}{0 .99} - \frac{1}{1}] = 3 .96 \approx 4 .$

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