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Q.

The wavelength of an electron of energy 100 eV will be

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a

$10 \overset{0}{A}$

b

$100 \overset{0}{A}$

c

$1.2 \overset{0}{A}$

d

1 $\overset{0}{A}$

answer is A.

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Detailed Solution

$∴ λ_{ele} = \sqrt{\frac{150}{V_{p_{d}}}} \overset{0}{A} = \frac{12.27}{\sqrt{V_{p_{d}}}} \overset{0}{A}$

$100 eV = {eV}_{p d}; ∴ V_{p d} = 100 V$

$∴ λ_{ele} = \frac{12.27}{\sqrt{100}} = 1.2 \overset{0}{A}$

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