The wavelength of first line of Balmer series is 6563 $\overset{0}{A}$ . The wavelength of first line of Lyman
series will be [Manipa12012]

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1215.4 $\overset{0}{A}$

600 $\overset{0}{A}$

7500 $\overset{0}{A}$

2500 $\overset{0}{A}$

answer is A.

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Detailed Solution

$\frac{λ_{Lyman}}{λ_{Balmer}} = \frac{(\frac{1}{2^{2}} - \frac{1}{3^{2}})}{(\frac{1}{1^{2}} - \frac{1}{2^{2}})} = \frac{5}{27}$ $[∵ \frac{1}{λ} = R (\frac{1}{n_{f}^{2}} - \frac{1}{n_{i}^{2}})]$

$\Rightarrow λ_{Lyman} = \frac{5}{27} \times λ_{Balmer} = \frac{5}{27} \times 6563 = 1215.4$ $\overset{0}{A}$

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