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Q.

The wavelength of light in vacuum is 5000 $\overset{o}{A}$ . When it travels normally through diamond of thickness 1.0mm, find the number of waves of light in 1.0mm of diamond. (Refractive index of diamond = 2.417)

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a

6834 waves

b

5834 waves

c

4384 waves

d

4834 waves

answer is A.

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Detailed Solution

$t = n λ^{'} = n \frac{λ}{μ}$

$\Rightarrow n = \frac{μ t}{λ}$

$\Rightarrow n = \frac{2.417 \times 10^{- 3}}{5000 \times 10^{- 10}} = 4834$

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