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Q.

The wavelength of light in vacuum is 5000 Ao . When it travels normally through diamond of thickness 1.0mm, find the number of waves of light in 1.0mm of diamond. (Refractive index of diamond = 2.417)

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a

6834 waves

b

5834 waves

c

4384 waves

d

4834 waves

answer is A.

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Detailed Solution

t=nλ'=nλμ

⇒n=μtλ

⇒n=2.417×10-35000×10-10=4834

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