The wavelength of Lyman series of hydrogen atom appears in

For Lyman series, minimum energy of the photon
$\begin{array}{r}{\mathrm{E}}_{min}=13.6\left(\frac{1}{1^2}-\frac{1}{2^2}\right)\\ =13.6\times \frac{3}{4}=10.2\mathrm{eV}\end{array}$
Maximum wavelength and maximum energy $=\frac{12400}{10.2}\approx 1215\text{Å}$
${\mathrm{E}}_{max}=13.6\left(\frac{1}{{\mathrm{I}}^2}\right)=13.6\mathrm{eV}$
Minimum wavelength $=\frac{12400}{13.6}=917\text{Å}$
So both minimum and maximum wavelength belongs to UV region.