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Q.

The wavelength of maximum emitted energy of a body at 700 K is 4.08µm. If the temperature of the body is raised to 1400 K, the wavelength of maximum emitted energy will be

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a

1.02 µm

b

16.32 µm

c

8.16 µm

d

2.04 µm

answer is D.

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Detailed Solution

T₁ = 700 K; T₂ = 1400 K

${(λ_{m})}_{1} = 4 .08 \times 10^{- 6} m, {(λ_{m})}_{2} = ?$

$\frac{{(λ_{m})}_{2}}{{(λ_{m})}_{1}} = \frac{T_{1}}{T_{2}}$

$\frac{{(λ_{m})}_{2}}{4 .08 \times 10^{- 6}} = \frac{700}{1400}$

${(λ_{m})}_{2} = 2 .04 μm$

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