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The wavelength of maximum emitted energy of a body at 700K is 4.08 m . If the temperature of the body is raised to 1400 K, the wavelength of maximum emitted energy will be

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1.02 $μ$ m

16.32 $μ$ m

8.16 $μ$ m

2.04 $μ$ m

answer is D.

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Detailed Solution

T₁ = 700k, T₂ = 1400k
${(λ_{m})}_{1} = 4.08 x 10^{- 6} m, {(λ_{m})}_{2} = ?; \frac{{(λ_{m})}_{2}}{{(λ_{m})}_{1}} = \frac{T_{1}}{T_{2}} \frac{{(λ_{m})}_{2}}{4.08 x 10^{- 6}} = \frac{700}{1400} \Rightarrow {(λ_{m})}_{2} = 2.04 μm$

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