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The wavelength of maximum intensity of radiation emitted by a star is 289.9 nm. The radiation intensity for the star is

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$10.67 \times 10^{14} W / m^{2}$

$5.67 \times 10^{8} W / m^{2}$

$10.67 \times 10^{7} W / m^{2}$

$5.67 \times 10^{- 12} W / m^{2}$

answer is A.

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Detailed Solution

$λ = 289.8 n m$ $T = \frac{b}{λ_{m}} = \frac{2.89 \times 10^{- 3}}{289.9 \times 10^{- 9}} = 10^{4} K$

$P = {σT}^{4} = 5.67 \times 10^{- 8} \times 10^{16} = 5.67 \times 10^{8} w / m^{2}$

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