The wavelength of sodium light in air is 5890A0. The velocity of light in air is 3×108 ms−1. The wavelength of light in a glass of refractive index 1.6, would be close to

Frequency does not depend on mediumμ1μ2=V2V1=λ2fλ1f⇒ μ2λ2=λ1μ1⇒μ2=58901.6=3681.25A0

The wavelength of sodium light in air is 5890A0. The velocity of light in air is 3×108 ms−1. The wavelength of light in a glass of refractive index 1.6, would be close to

Frequency does not depend on mediumμ1μ2=V2V1=λ2fλ1f⇒ μ2λ2=λ1μ1⇒μ2=58901.6=3681.25A0

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The wavelength of sodium light in air is $5890 \overset{0}{A}$ . The velocity of light in air is $3 \times 10^{8} m s^{- 1}$ . The wavelength of light in a glass of refractive index 1.6, would be close to

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$3680 \overset{0}{A}$

$5890 \overset{0}{A}$

$9424 \overset{0}{A}$

$15078 \overset{0}{A}$

answer is B.

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Frequency does not depend on medium

$\begin{array}{l} \frac{μ_{1}}{μ_{2}} = \frac{V_{2}}{V_{1}} = \frac{λ_{2} f}{λ_{1} f} \\ \Rightarrow μ_{2} λ_{2} = λ_{1} μ_{1} \\ \Rightarrow μ_{2} = \frac{5890}{1.6} = 3681.25 \overset{0}{A} \end{array}$

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The wavelength of sodium light in air is 5890A0. The velocity of light in air is 3×108 ms−1. The wavelength of light in a glass of refractive index 1.6, would be close to

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The wavelength of sodium light in air is $5890 \overset{0}{A}$ . The velocity of light in air is $3 \times 10^{8} m s^{- 1}$ . The wavelength of light in a glass of refractive index 1.6, would be close to