Q.

The wavelength of the first line in Balmer series in the hydrogen spectrum is λ . What is the wavelength of the second line ?

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a

3λ16

b

20λ27

c

5λ36

d

3λ4

answer is A.

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Detailed Solution

1λ=R(1n121n22)

first line n2=3 n1=2  second line n2=4 n1=2

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