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The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1 would be $(Rydberg constant = 1.097 \times 10^{7} m^{- 1})$

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91nm

192 nm

406 nm

$9.1 \times 10^{- 8} nm$

answer is A.

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Detailed Solution

$\bar{ϑ} = \frac{1}{λ} = R [\frac{1}{1} = \frac{1}{\infty^{2}}]$

$λ = \frac{1}{R} = 0.000009117 cm$

$λ = 9 1 \times 10^{- 7} cm$

$λ = 91 nm$

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