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Q.

The wavelength λeof an electron and λpof a photon of same energy E are related by

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a

λpλe

b

λpλe2

c

λpλe

d

λp1λe

answer is C.

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Detailed Solution

Wavelength of an electron of energy E is

λe=h2meE          i

Wavelength of a photon of same energy E is

λp=hcE    or   E=hcλp          ii

Squaring both sides of Eq. (i), we get

λe2=h22meE   or  E=h22meλe2        iii

Equating (ii) and (iii), we get

hcλp=h22meλe2 λp=2mechλe2 λpλe2

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