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Q.

The wavelengths of two sound notes in air are 40/195m and 40/193m. Each note produces 9 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/s is

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a

360

b

320

c

300

d

340

answer is A.

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Detailed Solution

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n1=Vλ1=195V40 ; n2=Vλ1=193V40 ; n1-n=9
n2-n=9 ; n1 - n2 = 18 ;

18=v40(195-193)
⇒v = 360 ms-1

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