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Q.

The weight (mg) of PbS that get precipitated form a 1.0 L saturated PbSO4  solution if the    solution is made saturated withH2S  (0.1 M) and pH adjusted to 0 is Z. The value of Z4  is _________.
(Round off to the nearest integer).
[Ksp of PbSO4=1.6×10-8 and Ksp of PbS=2.5×10-27. For H2S; Ka1=10-7 and Ka2=10-14  Atomic weight  Pb = 206 and S = 32
 

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Detailed Solution

The precipitate exchange equilibrium is:
 PbSO4+S2PbS+SO42   K=SO42S2=6.4×1018
Also for  H2S:Ka=1021=H+2S2H2SS2=1022SO42=6.4×104
Hence,  Pb2 present=2.5×10-5M
Initial Pb2+ =1.26×10-4M moles of PbS precipitated  =104
 mPbS=23.8 mg.
 

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The weight (mg) of PbS that get precipitated form a 1.0 L saturated PbSO4  solution if the    solution is made saturated withH2S  (0.1 M) and pH adjusted to 0 is Z. The value of Z4  is _________.(Round off to the nearest integer).[Ksp of PbSO4=1.6×10-8 and Ksp of PbS=2.5×10-27. For H2S; Ka1=10-7 and Ka2=10-14  Atomic weight  Pb = 206 and S = 32