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Q.

The weight of 0.1 mole of ${Na}_{2} {CO}_{3} is$

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a

5.3 g

b

10.6 g

c

106 g

d

$6.02 \times 10^{22} g$

answer is B.

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Detailed Solution

1 mole of ${Na}_{2} {CO}_{3}$ =106g

0.1mole of ${Na}_{2} {CO}_{3}$ $\frac{106 g}{1 mol {Na}_{2} {CO}_{3}} \times 0.1 m o l e o f$ ${Na}_{2} {CO}_{3}$ =106g

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