The weight of 1×1022 molecules of CuSO4.5H2O is …..[NA=6×1023, At wt Cu=63.5,S=32,H=1,O=16]

6×1023→249.5 gr1×1022→?1×1022×249.56×1023=41.58×10−1=4.158=4.16 gr

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The weight of $1 \times 10^{22}$ molecules of $C u S O_{4} .5 H_{2} O$ is ….. $[N A = 6 \times 10^{23}, At wt C u = 63.5, S = 32, H = 1, O = 16]$

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answer is 4.14.

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$6 \times 10^{23} \to 249.5 g r$

$1 \times 10^{22} \to ?$

$\frac{1 \times 10^{22} \times 249.5}{6 \times 10^{23}} = 41.58 \times 10^{- 1} = 4.158 = 4.16 g r$

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