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The weight of a body at the surface of earth is 18N. the weight of the body at an altitude of 3200km above the earth’s surface is $(Re = 6400 k m)$

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8 N

9.8 N

4.9 N

19.6 N

answer is C.

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Detailed Solution

At a height ‘h’

$g_{h} = g {(\frac{R}{R + h})}^{2}$

Weight of the body at a height

$m g_{h} = m g {(\frac{R}{R + h})}^{2} = 18 {(\frac{6400}{6400 + 3200})}^{2} = 8 N$

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