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The weight of a body on the earth is 400 N. Then weight of the body when taken to a depth half of the radius of the earth will be

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300 N

200 N

Zero

100 N

answer is D.

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Detailed Solution

$\begin{array}{l} W = mg = 400 N \\ W^{1} = {mg}^{1} = mg [1 - \frac{d}{R}] here d = \frac{R}{2} \\ W^{1} = mg [1 - \frac{1}{2}] = \frac{mg}{2} = 200 N \end{array}$

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