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The weight of a man is 750 N. The total area of the soles of his shoes is $250 {cm}^{2}$ . Find the pressure he applies on the floor

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150 Pa

300 Pa

30,000 Pa

$3 \times 10^{6} Pa$

answer is A.

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Detailed Solution

$Force = 750 N Area = 250 {cm}^{2} = 250 \times 10^{- 4} m^{2} Pr essure = \frac{Force}{Area} = \frac{750}{250} \times 10^{4} N / m^{2} = 30, 000 Pa$

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