The weight of iron which will be converted into its oxide (Fe₃O₄ ) by the action of 18g of steam on it will be (Atomic weight of Fe=56)
( $3 Fe + 4 H_{2} O \to {Fe}_{3} O_{4} + 4 H_{2}$ )

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168 g

84 g

42 g

21 g

answer is C.

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Detailed Solution

$3 Fe + 4 H_{2} O \to {Fe}_{3} O_{4} + 4 H_{2}$
3X56 4X18
=168 =72
$∴$ 72g steam required 168g of Fe
18g steam required ____?
$\frac{18}{72} \times 168 = 42 g$

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