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The weight of iron which will be converted into its oxide ( $F e_{3} O_{4}$ ) by the action of 18g of steam on it will be (Atomic weight of Fe=56)

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168g

84g

42g

21g

answer is C.

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Detailed Solution

$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$

$3 \times 56 4 \times 18$
=168 =72
$∴$ 72g steam required 168g of Fe
$\frac{18}{72} \times 168 = 42 g$ 18g steam required ____?

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