The weight of one litre of a gas at 1atm pressure and 300K is 4g. At what temperature the weight of the gas is 4g when the pressure is made 0.5 atm and volume is 1 litre?

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answer is B.

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Detailed Solution

Given

$W_{1} = 4 g W_{2} = 4 g$

$V_{1} = IL V_{2} = IL$

$P_{1} = 1 atm P_{2} = 0.5 atm$

$T_{1} = 300 k T_{2} = ?$

$\frac{P_{1} V_{1}}{P_{2} V_{2}} = \frac{W_{1} T_{1}}{W_{2} T_{2}}$

$if W_{1} = W_{2}$

$\frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}}$

$\frac{1}{0.5} = \frac{300}{T_{2}}$

$T_{2} = 300 \times 0.5$

$T_{2} = 150 K$

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