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The weight of potassium in 0.25 moles of ${KNO}_{3}$ is

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7.25g

9.75g

6.25g

8.25g

answer is C.

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Detailed Solution

$\begin{array}{l} {1 mole ofKNO}_{3} \to 39 g of potassium \\ 0. {25 moles of KNO}_{3} \to ? g of potassium \\ 39 \times 0.25 = 1 \times x \\ x = \frac{39 \times 0.25}{1} = 9.75 g of potassium \end{array}$

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